3a+2[2+3(a-1)]=(2y+8)

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Solution for 3a+2[2+3(a-1)]=(2y+8) equation:


Simplifying
3a + 2[2 + 3(a + -1)] = (2y + 8)

Reorder the terms:
3a + 2[2 + 3(-1 + a)] = (2y + 8)
3a + 2[2 + (-1 * 3 + a * 3)] = (2y + 8)
3a + 2[2 + (-3 + 3a)] = (2y + 8)

Combine like terms: 2 + -3 = -1
3a + 2[-1 + 3a] = (2y + 8)
3a + [-1 * 2 + 3a * 2] = (2y + 8)
3a + [-2 + 6a] = (2y + 8)

Reorder the terms:
-2 + 3a + 6a = (2y + 8)

Combine like terms: 3a + 6a = 9a
-2 + 9a = (2y + 8)

Reorder the terms:
-2 + 9a = (8 + 2y)

Remove parenthesis around (8 + 2y)
-2 + 9a = 8 + 2y

Solving
-2 + 9a = 8 + 2y

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 9a = 8 + 2 + 2y

Combine like terms: -2 + 2 = 0
0 + 9a = 8 + 2 + 2y
9a = 8 + 2 + 2y

Combine like terms: 8 + 2 = 10
9a = 10 + 2y

Divide each side by '9'.
a = 1.111111111 + 0.2222222222y

Simplifying
a = 1.111111111 + 0.2222222222y

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